Order Integrated Rate Law Graph Slope vs. t k Express your answer with the appro
ID: 520828 • Letter: O
Question
Order Integrated Rate Law Graph Slope vs. t k Express your answer with the appropriate un Indicate the multiplication of units, as necessary, explicitly either with a multiplication do or a dash. 4 M 4.32.10 kuth Submit Hints My Answers Give Up Review Part incorrect Try Again 2 attempts remaining Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate un Indicate the multiplication of units, as necessary, explicitly either with a multiplication do dash. 11:13 AM Pa 69%. 4/28/2017Explanation / Answer
A)The units of k for a zero order reaction is mol/ L*1/ sec=M.(1/s)
part-B)zero order is rate independent
c)
For a first order reaction,
ln[A/A0]=-kt
Here, A is the concentration at ant time t, and the A0 is the concentration at time t=0, initially.
k is the rate constant, t is the time
ln[A]=kt+ln[A0]=9*10^-2=-15k+ln[A0]------------->1
ln[A]=kt+ln[A0]=4.3*10^-3=-75k+ln[A0]--------->2
0.0857=60k
k=0.0014 sec
--------------------------------
part-D)
1/[A] =kt+1/[A0]
1/0.28 M =270 k +1/[A0]-----------------1
1/0.06 M =710 k +1/[A0]-------------2
Solve both the equations
-13.09=-440 k
k=0.02975 L/mol sec =M-1 s-1
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