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Order Integrated Rate Law Graph Slope vs. t k Express your answer with the appro

ID: 520828 • Letter: O

Question

Order Integrated Rate Law Graph Slope vs. t k Express your answer with the appropriate un Indicate the multiplication of units, as necessary, explicitly either with a multiplication do or a dash. 4 M 4.32.10 kuth Submit Hints My Answers Give Up Review Part incorrect Try Again 2 attempts remaining Part B What was the initial reactant concentration for the reaction described in Part A? Express your answer with the appropriate un Indicate the multiplication of units, as necessary, explicitly either with a multiplication do dash. 11:13 AM Pa 69%. 4/28/2017

Explanation / Answer

A)The units of k for a zero order reaction is mol/ L*1/ sec=M.(1/s)

part-B)zero order is rate independent

c)

For a first order reaction,

ln[A/A0]=-kt

Here, A is the concentration at ant time t, and the A0 is the concentration at time t=0, initially.

k is the rate constant, t is the time

ln[A]=kt+ln[A0]=9*10^-2=-15k+ln[A0]------------->1

ln[A]=kt+ln[A0]=4.3*10^-3=-75k+ln[A0]--------->2

0.0857=60k

k=0.0014 sec

--------------------------------

part-D)

1/[A] =kt+1/[A0]

1/0.28 M =270 k +1/[A0]-----------------1

1/0.06 M =710 k +1/[A0]-------------2

Solve both the equations

-13.09=-440 k

k=0.02975 L/mol sec =M-1 s-1

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