Which of the following is the electron dot formula for an atom of carbon? A) (a)
ID: 521074 • Letter: W
Question
Which of the following is the electron dot formula for an atom of carbon? A) (a) B) (b) C) (c) D) (d) E) (e) Which of the following elements has the lowest ionization energy? A) 1s^2 2s^2 2p^6 3s^2 3p^6 B) 1s^2 2s^2 3p^6 4s^2 5p^6 C) 1s^2 2s^2 p^6 3s^2 p^6 D) 1s^2 2s^2 2p^6 3s^2 3p^5 E) 1s^2 2s^2 2p^6 3s^2 4p^6 Give the complete electronic configuration for A) 1s^2 2s^2 2p^63s^23p^6 B) 1s^2 2s^2 3p^6 4s^2 5p^6 C) 1s^22s^2p^63s^2p^6 D) 1s^22s^22p^63s^23p^5 Give the complete electronic configuration for S^2-. A) 1s^22s^22p^63s^24p^6 B) 1s^22s^23p^64s^25p^6 C) 1s^22s^22p^63s^23p^6 D) 1s^22s^2p^63s^2p^6 E) 1s^22s^22p^63s^23p^5 Place the following in order of decreasing magnitude of lattice energy. K_2O Rb_2S Li_2O A) Rb2S > K_2O > Li_2O B) Li_2O > Rb_2S > K_2O C) Rb_2S > Li_2O > K_2O D) L_i2O > K_2O > Rb_2S E) K_2O > Li_2O > Rb_2SExplanation / Answer
31 The answer is C, as carbon has 4 electron in its valence shell
32. The answer is E, as the ionization eneergy decreaces down the group, will have lower ionization energy than potassium, The rest of the elemnts mentioned belong to group 2, their ionization energy is larger than group 1 element.
33. The answer is A
As calcium in ground state has electronic configuration of 1s22s22p63s23p64s2
Ca2+ electronic configuration will be1s22s22p63s23p6
34 The answer is C
As Sulphur in ground state has electronic configuration of 1s22s22p63s23p4
Ca2+ electronic configuration will be1s22s22p63s23p6
35. The answer is D
Li2O > K2O > Rb2S
Due to small radius of Li will have larger lattice energy
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