The Figure shown below is the heating curve obtained by heating 28.7 g of water

Question

The Figure shown below is the heating curve obtained by heating 28.7 g of water from -10.0 to 140.00c The region labeled a represents the heating of ice to its melting point; the region b represents the melting of ice to form liquid water; region c represents the heating of water to its boiling point and region d represents boiling the water to convert it to a vapor. Useful data is also displayed under the heating curve. Use this figure to answer the next 4 questions. 140oC Temperature 100°C 0°C 10°C L heat added specific heat capacity ice 2.09 J/goC AH fusion 6.02 kJ/mol specific heat capacity water 4.18 J/goc AH, vaporization 40.7 kJ/mol specific heat capacity steam 2.00 J/goC

Explanation / Answer

1. We know that heat absorbed is:-

q=ms*change in temperature

Where m=mass of sample=28.7g=0.0287Kg

s=specific heat of ice=2.1KJ/Kg-k

Change in temperature =0-(-6.97)=6.97

q=0.42 KJ

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