The following three solutions were analyzed according to the scheme used in this

Question

The following three solutions were analyzed according to the scheme used in this experiment. Which one, if any, of the ions treated, is present in each solution? If the data indicate that none of the six is present, write the word "None" as your answer. (a) Silver Nitrate Test. Yellow precipitate formed, which dissolved in dilute nitric acid. Barium chloride Test. White precipitate formed, which dissolved in dilute hydrochloric acid. Organic Solvent Test. The decane layer remained almost colorless after treatment with chlorine water. (b) Silver Nitrate Test. Red precipitate formed, which dissolved in dilute nitric acid to give an orange solution. Barium Chloride Test. Yellow precipitate formed, which dissolved in dilute hydrochloric acid to give an orange solution. Organic Solvent Test. The decane layer remained almost colorless after treatment with chlorine water. (c) Silver Nitrate Test. Yellow precipitate formed, which did not dissolve in dilute nitric acid. Barium Chloride Test. No precipitate formed. Organic solvent Test. The decane layer turned reddish-brown.

Explanation / Answer

1. Qualitative analysis

(a) Gives yellow precipitate with AgNO3 : I- present

forms white precipitate of BaI2

Anion Present : I-

(b) Forms red precipitate wth AgNO3 and yellow precipitate with BaCl2

Anion Present : CrO4^2-

(c) Forms yellow precipitate with AgNO3 and no precipitate with BaCl2

Anion Present : Br-

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