When 1.510 x 10^3 J of heat energy is added to 41.7 g of hexane, C6H14, the temp

Question

When 1.510 x 10^3 J of heat energy is added to 41.7 g of hexane, C6H14, the temperature increases by 16.0°C. Calculate the molar heat capacity of C6H14 Bookmarks Tools Window Help Blinn College Bryan Campus x c Search modibis/view.php?ida 3267630 Twitter W wikipedia Y Yahoo! Ga News. Ga popular Campus Not set 24.2/100 Gradebook Print calculator Periodic Table 4 12 General Chemistry 4th Edition University Science Books presented by Sapling Leaming When 1.510 x10aJof heat energy is added to 41.7 g of hexane.coHse. the temperature increases by 16.0 Calculate the molar heat capacity of CeHs. JI (mo Previous ® Give up a view Sotulion Check Answer ONext HExt about us l careers privacy policy terms of use contact us help

Explanation / Answer

Q = 1.510 x 10^3 J = 1510 J

moles of hexane = 41.7 / 86 = 0.484

dT = 16.0 oC

Q = n Cp dT

Cp = Q / n dT

Cp = 1510 / 0.484 x 16

Cp = 195 J / mol .o C

molar heat capacity = 195 J / mol .o C

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