Given the balance equation which combination of reactants will result in natural

Question

Given the balance equation which combination of reactants will result in natural product future? HCI(aq) + NaOH(aq) rightarrow H_2O(i) - NaCI (aq) I because HCI and NaOH have equal male proportions II because HCI and NaoH have the same volumes Ill because HCI and NaoH have the same concentrations. I, II, and Ill because HCI and NaOH produce neutral salt water product mixture in all cases. I, II, and Ill because HCI and NaoH produce a neutral salt water product mixture in all cases What volume of a 0.250 M AgNO, solution is required to react to completion with 0.300 L of0350 M Na_2 S? 2AgNO_3 (aq) + Na_2S(aq) rightarrow AgS(s) + 2NaNO_2(aq) 52.5 mL 210 mL 420 mL $40 mL What mass of H_2O is produced when excess CH_3OH reacts with 0.500 moles of O_2? 2CH_3OH(I) + 3O_2(g) rightarrow 2CO_2(g) + 4H_2O(g) 36.0 g 18.0 g 12.0 g 9.00 g What do the three pictures represent? Different elements isotopes of the same element

Explanation / Answer

Q. 22

HCl is acid and NaOH is base.

We know when HCl ( strong acid) reacts with NaOH ( strong base) it will form water and salt.

Neutral salt is formed from the strong acid and strong base. Both HCl and NaOH are strong so they will form NaCl and water and it does not depend on the proportion of these.

So the answer would be option d ( I , II and III )

Q. 23

We are given the reaction.

Mol ratio between AgNO3 to Na2S is 2:1. This means that 1 mol of Na2S needs 2 mol AgNO3.

Lets calculate moles of Na2S

Mol of Na2S = volume in L x molarity = 0.300 L x 0.350 M = 0.105 mol

Now calculation of moles of AgNO3

0.105 mol Na2S x 2 mol AgNO3 / 1 mol Na2S = 0.21 mol AgNO3

We know volume in L = mol / Molarity

So, volume = 0.21 mol AgNO3 / 0.250 M = 0.84 L = 840 mL

So the correct option is option “D” 840 mL

Q. 24

We use the mol ratio between O2 and H2O which is 3 mol O2 : 4 mol H2O

So the mol ratio between O2 : H2O is 3:4

Lets find moles of H2O using moles of O2

Moles of H2O = 0.500 mol O2 x 4 mol H2O / 3 mol O2 = 0.667 mol H2O

Mass of H2O = mol of H2O x molar mass of H2O = 0.667 mol x 18.0148 g/mol = 21.01 g H2O

Answer is option C 12.0 g

Q. 25

We know, isotopes have same number of proton and electron but different neutrons so these given structures are for isotopes.

Answer is “isotopes”

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