The appropriate unit for a zeroth-order rate constant is A) M/s B) 1/M middot s
ID: 522520 • Letter: T
Question
The appropriate unit for a zeroth-order rate constant is A) M/s B) 1/M middot s c) 1/s D) 1/M^2 middot s is When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this phenomenon is that as the reactant concentration increases, A) the average kinetic energy of molecules increases. B) the activation energy increases. C) the frequency of molecular collisions increases. D) the rate constant increases. E) the order of reaction increases For the reaction whose rate law is rate = k[X], a plot of which of the following is a straight line? A) [X] versus time B) [X] versus 1/time C) ln [X] versus time D) ln [X] versus 1/time E) 1/[X] versus time Consider the following equilibrium, 4NH_3(g) + 3O_2(g) rightarrow 2N_2(g) + 6H_2O(g) + 1531 kJ When nitrogen gas was added to the system, the concentrations of the reactants would A) increase. B) decrease. C) remain constant. D) more information is needed to predict.Explanation / Answer
8) for a zero order reaction rate law is
kt = x
or k = x/t Thus k has the same units as that of rate of reaction mol/L.sec. or M/s
9) option C
When the [reactant] increases, more molecules , more collisions . thus rate of rxn increases.
10)option C
rate = k[X]
that is it is first order reaction.
For first order reaction the graph between time and ln[X] is a striaght line with negative slope.
t= (2.303/k) log [X]o/[X]t
11)option A
when te product N2 is added to the system .the equilibrium shifts to left side , towards the reactants.
Thus [reactants] increases.
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