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34. The nitro (NOi) group is a very strong group and it is a powerful director a

ID: 523274 • Letter: 3

Question

34. The nitro (NOi) group is a very strong group and it is a powerful director a deactivating, ortho-para b, activating, meta c, deactivating, meta d. activating, ortho-para 35. In aldehydes, where one group is a hydrogen atom, the central carbon of the tetrahedral product formed from the aldehyde is less crowded and the product is less stable. True b, False 36. All electron-donating groups are activating groups and all are ortho para directors with the exception of substituents, all electron-withdrawing groups are deactivating groups and all are meta directors. a hydroxyl b, amino c. halogens d, alkoxyl 37. Hydrogen abstraction from the methyl group of methylbenzene (toluene) produces a radical called the radical. a. allylic c, halogen d. benzyllic 38. Groups that have an unshared electron pair on the atom attached to the aromatic ring that make the ring more reactive than benzene are groups and are directors a, deactivating, ortho-para b, activating, meta c, deactivating, meta d activating, ortho-para

Explanation / Answer

34) Since nitro group has strong electron withdrawing capcity due to -R effect,it decreases the electron density in aromtic ring and hence it deactivate it for aromatic electrophilic substituion. Out of ortho, meta and para positions, ortho and para positions are most deactivated so substitution occur at meta position.

so answer is C, deactivating and meta

35) False, as the tetrahedral intermediate with angle of 109 degree (than 120 degree in aldehyde ) will be more crowded and also sigma bond is formed on expense of pi bond so the product will be more stable

36) Answer is C

Halogen though are electronwithdrawing due to -I effect but they are ortho and para directing due to +R effect which increases the electron density at ortho and para position.

37) Hydrogen abstraction from methyl benzene (Toluene) produces benzyl radical, so answer is D

38) Group that have unshared pair of electron increases the electron density at ortho and para position due to +R effect. So they are activaing group and orhto para directing

So answer is D

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