The amount of ammonium chloride formed the neacti hydrogen chloride 34092 454,80

Question

The amount of ammonium chloride formed the neacti hydrogen chloride 34092 454,80 474.28 50569 g i. None of the above, de amount is 9. The oxidation number of sulfur in the following compounds is as follows: Oxidation number of sulfur oxidation number of sulfur Oxidation number of sulfur Oxidation number of sulfur Oxidation number of sulfur oxidation number of sulfur HS 10. For the following unbalanced molecular equations UME).write down the corresponding balanced molecular equation BME), the complete ionic equation (CIE and the net ionicequation oNIE: NIE

Explanation / Answer

9) H2S ,Oxidation number of sulfur => 2 + x = 0 => x = -2

Na2SO4 ,Oxidation number of sulfur =>2+x +4(-2)=0 => 2 +x -8 =0 => x = +6

Na2SO3 ,Oxidation number of sulfur => 2 +x + 3(-2)=0 =>2+x-6=0 =>x = +4

Na2S2O3 ,Oxidation number of sulfur => 2 + 2x +3(-2)=0 => 2+ 2x -6 =0=> x =+2

SO2,Oxidation number of sulfur => x + 2(-2) =0 => x -4 =0 => x = +4

HS- ,Oxidation number of sulfur => 1+ x =-1 => x = -2

10)   Ba(OH)2(aq) + NH4Cl(aq) ----> BaCl2(aq) + NH3(g) +H2O(l)

Balanced molecular equation(BME) is---

Ba(OH)2(aq) + 2 NH4Cl(aq) ----> BaCl2(aq) + 2NH3(g) +2H2O(l)

Complete ionic equation(CIE) is----

Ba2+(aq) + 2OH-(aq) +2NH4+(aq) +2Cl-(aq) ----> Ba2+(aq) +2Cl-(aq) + 2NH3(g) +2H2O(l)

Net ionic equation(NIE) is---

2OH-(aq) +2NH4+(aq) ---->  2NH3(g) +2H2O(l)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.