1) Sketch what the Michaelis-Menten hyperbolic plot and the Lineweaver-Burk reci
ID: 524220 • Letter: 1
Question
1) Sketch what the Michaelis-Menten hyperbolic plot and the Lineweaver-Burk reciprocal plot would look like for an enzyme with and without a competitive inhibitor. Plot with and without inhibitor on the same axes, and correctly label each axis. On both plots, indicate KM (and KM) and Vmax, or how you would determine these from the reciprocal plots.
Once you have completed this, do the same for an enzyme with and without an irreversible inhibitor. Why does the KM change with the competitive inhibitor but not the irreversible inhibitor?
Explain this in three sentences or less (treat this as practice for the exam—you will need to be able to explain things accurately and concisely, and points will be deducted for unfocused regurgitation).
2) For a chemical reaction, Keq = 0.73. Which of the following can you conclude about this reaction? Do not use any formulas or calculations to determine your answer. (Select all that apply)
a. G°’ = 0 ____ b. The reaction is exergonic ____ c. The value of G°’ is positive ____
d. This reaction could not go in the forward direction under physiologic conditions ____ e. This reaction could go in the forward direction under physiologic conditions ____
Explanation / Answer
Q2)
if Keq = 0.73, then this is favouring REACTANTS
therefore, dG > 0,
this reaction is not likely to go forward, bur backwards
best answer
d. This reaction could not go in the forward direction under physiologic conditions ____
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