Draw a voltaic cell that is constructed with a Mn/Mn^2+ electrode and a Cd/Cd^2+

Question

Draw a voltaic cell that is constructed with a Mn/Mn^2+ electrode and a Cd/Cd^2+ electrode. Use the standard table 18.1 your textbook to determine which will be the cathode and which will be the anode. Your drawing should include all of the following components: a. Label the location of each substance (Mn, Mn^2+, Cd and Cd^2+) b. Label the cathode and the anode c. Label the direction of electron flow d. Label which electrode is positively charged and which is negatively charged e. Include a salt bridge with NaNO_3, . Label the direction that each ion flows. f. Write the cell notation for this voltaic cell g. Calculate the cell potential of this cell

Explanation / Answer

SRP of Mn = -1.18V

SRP of Cd = -0.40V

Thus Mn is oxidised and Cd is reduced.

a)So construct a cell with Mn half cell on left hand side and Cd on right hand side connected by slat bridge.

b) Mn half cell is the anode and Cd half cell is the cathode

c) Electrons flow from Mn to Cd in external circuit.

d) Mn -------> Mn+2 + 2e-

Mn cell is negatively charged

Cd+2 +2e- -------> Cd

Cd is positively charged.

e) in the salt bridge, NO3- flows towards anode/Mn half cell

Na+ move towards cathode / Cad half cell

f) The cell reaction is Mn + Cd+2 ----------> Cd + Mn+2

cell notation is

Mn/Mn+2||Cd+2/Cd

g)Eo cell = SRP of cathode - SRP of anode

= -0.40 -(-1.18) V

=+0.78V

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