At the end of 2012, global population was about 7 0 billion people. What mass of

Question

At the end of 2012, global population was about 7 0 billion people. What mass of glucose in kg would be needed to provide 1600 cal/person/day of nourishment to the global population for one year? Assume that glucose is metabolized entirely to CO_2 (g) and H_2O(l) according to the following thermochemical equation: C_6H_12 O_6(s)+ 6O_2(g) rightarrow 6CO_2(g) + 6H_2O(l) Delta H degree = 2803 kJ Express your answer to two significant figures and include the appropriate units. Mass = _________________ ________________

Explanation / Answer

1 Kcal = 4.184 Kj

Glucose consumption = No of people x Consumption per person per day x 365 days

= 7 x 109 x 1600 x 365

= 4.088 x 1016 Cal

= 4.088 x 1013 Kcal

= 4.088 x 4.184 x 1013 KJ

= 1.71 x 1014 KJ

Now molar mass of glucose = (6x12)+(12x1)+(6x16)

= 72+12+96 = 180 g

Energy released per gm = 2803 KJ

Mass of glucose needed = (1.71 x 1014) / (2803/180) gm

= (1.71 x 1014 x 180) / 2803

= 1.098 x 1013 g

= 1.098 x 1010 kg

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