Experiment Cobalt(II) ions. can form an aquo complex Co(Hzo) that is pink in col
ID: 525255 • Letter: E
Question
Experiment Cobalt(II) ions. can form an aquo complex Co(Hzo) that is pink in color, and a chloro complex Coay that is blue, 6, H20 CoC14 (aq) Co(H2006 z (aq) 40i (aq) heat blue pink Experimental Prepare the aquo complex by dissolving about o 26 g of cobalt chloride crystals Co(H20%C2. n 10 mL water. a Put 4mL of the aqua complex in a 25 ml beaker. slowly add 8 mL of concentrated HCI. Keep this solution you wi use it in the next two btuc b) Put 2 mL of the solution from step a in a test tube. Add 2 mL of (c) water. Wish test tube. Add t another 2 ml of solution from step a in a second o.1M silver in 10 mL water) dropwise. Pink d Put 4 mL the initial pink aquo complex in a ml beaker. slowly add 4 ml of concentrated HCI. Prepare three test tubes each containing 2 mL of this solution. one tube in a hot water bath, cool the second Heat tube ice bath, leave the third tube at room temperature for stay the a in an and CHotblue) ture gi What is the CLcet urn Pin acid in step Same purele effect of the addition of hydrochloric a? Can you rationalize the changes caused by the addition of water and silver mitrade in steps b and c Q3 How does the heating cooling shift the librium in step d? equiExplanation / Answer
2) The student got the following results:
11.8/22 = (0.0020/0.0040)m = (1/2)m
The student approximated 11.8/22 as 11/22 and wrote
11/22 = (1/2)m
===> 1/2 = (1/2)m
===> (1/2)1 = (1/2)m
Therefore, the approximate value of m is m = 1 (ans).
The actual value of m is obtained by taking logarithm on both sides.
log (11.8/22) = log (1/2)m
===> log (11.8/22) = m*log (1/2)
===> -0.2705 = m*(-0.3010)
===> m = (-0.2705)/(-0.3010) = 0.8987 0.900 (ans)
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