If 23.6 g of CaCI_2(110.98 g/mol) are dissolved in 200.0 mL of pure water, what

Question

If 23.6 g of CaCI_2(110.98 g/mol) are dissolved in 200.0 mL of pure water, what is concentration of the solution, in M, in g/M, and in ppm (parts per million)? Ans. ___ M Ans. ___ g/L Ans.___ ppm Calculate the number of oxygen atoms in 12.0 g of methanol, CH_3OH (32.04g/mol). Ans. ___ Molecule B has hydrogen bonds; Molecule A is non-polar. Which of the molecular liquids will have the higher boiling point? Why? Which of these molecular liquids, A or B, will have the lower vapor pressure? Circle A or B. Explain why. Which cation has the larger radius, Na^+ or Mg^2+? ___ Why? ___ Which anion has the larger radius, Br or I? __ Why? ___

Explanation / Answer

mass of Cacl2= 23.6, volume of water= 200ml=200/1000 L= 0.2L

concentration = 23.6/200 g/ml= 0.118 g/ml

moles of CaCl2 in 23.6 gm = mass/molar mass= 23.6/110.98 =0.2126 moles

concentration in M= moles/L= 0.2126/0.2= 1.063M

0.118 g/ml= 0.118*1000mg/10-3 L ( 1ml=10-3L) =0.118*106 mg/L ( 1mg/L= 1ppm) =0.118*106 ppm

2. moles of methanol in 12 gm = mass/molar mass= 12/32.04= 0.374 moles

CH3OH ( methanol) ----->C+2H2+1/2O2

0.374 moles of methanol contains 1 atom of oxygen. hence 0.374 atoms of oxygen is there is 12 gm of methanol.

3. Non polar molecules will have lower boilng than molecules possesing hydrogen bonding due to hydrogen bonding being extreme type of dipole-dipole bonding. As a result, B will have lower vapor pressure.

4. Na+ will have larger ionic radius than Mg+ becuase Mg+2 has one more proton than sodium.

5.

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