Write the net ionic equations for the reactions below. Give the names for the se

Question

Write the net ionic equations for the reactions below. Give the names for the sectator ions. a. Al(NO_3)_3 + NaOH rightarrow Al(OH)_3 + NaNO_3 spectator ions: b. CuBr_2 + K_2SO_4 rightarrow 2 KBr + CuSO_4 spectator ions: Correctly label each of the reactions below as double replacement, single replacement, synthesis, or decomposition. Circle the acid-base reaction(s). Draw a box around the combustion reaction(s). a. 2 KNO_3 rightarrow 2 KNO_2 + O_2 b. H_2C_2O_4 + Ba(OH)_2 rightarrow 2 HOH + BaC_2O_4 Consider the redox reaction below. 2 Li + Mg(ClO_3)_2 rightarrow Mg + 2 LiClO_3 a. Calculate the oxidation number for each atom on the reactant side. b. What is being oxidized? c. Which reactant is the oxidizing agent? Given the data below, list Na, Cr, and Rb in order of increasing activity: Na + RbNO_3 rightarrow NR Cr + NaNO_3 rightarrow NR Write formulas for the names and names for the formulas. a. Mg(ClO_3)_2 b. calcium sulfate c. (NH_4)_3 P d. hydroiodic acid e. KF f. tin(IV) nitride

Explanation / Answer

Q1.

net ionic equations:

balance equation:

Al(NO3)3 + NaOH = Al(OH)3 + NaNO3

balance OH

Al(NO3)3 + 3NaOH = Al(OH)3 + NaNO3

balance Na

Al(NO3)3(aq) + 3NaOH(aq) = Al(OH)3(s) + 3NaNO3(aq)

now

net ionic is only solid formation ions

spectator ions:

Na+ and NO3-

the net ionic:

Al+3(aq) + 3OH-(aq) = Al(OH)3(s)

b)

CuBr2 + K2SO4 --> 2KBr + CuSO4

balance is already done

split in ions

Cu2+ + 2Br- + 2K+ + SO4-2 --> 2K+ + 2Br- + CuSO4(s)

note that Br- and K+ are spectator ions

so

Cu2+(aq) + SO4-2(aq) = CuSO4(s)

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