NO HAND WRITTEN ANSWERS Propane (C 3 H 8 ) burns in oxygen to produce carbon dio

Question

NO HAND WRITTEN ANSWERS

Propane (C3H8) burns in oxygen to produce carbon dioxide gas and water vapor. (a) Write a balanced equation for this reaction. (b) Calculate the number of liters of carbon dioxide measured at STP that could be produced from 7.45 g of propane. (10 points)

(Reference: Chang 5.109)

A 10.0 g piece of pure aluminum is placed in 75.0 mL of 0.54 M hydrochloric acid at STP condition. They react as follows:

2Al + 6HCl 3H2(g) + 2AlCl3

Calculate the following:

Volume, in liters, of hydrogen gas. (5 points)

Molarity of Al+3. (Assume 75.0 mL solution.) (5 points)

Molarity of Cl–. (Assume 75.0 mL solution.) (5 points)

Explanation / Answer

Q1.

Propane (C3H8) burns in oxygen to produce carbon dioxide gas and water vapor.

(a) Write a balanced equation for this reaction.

C3H8 + O2 = CO2 + H2O

balance C

C3H8 + O2 = 3CO2 + H2O

balance H

C3H8 + O2 = 3CO2 + 4H2O

balace O

C3H8 + 5O2 = 3CO2 + 4H2O

(b) Calculate the number of liters of carbon dioxide measured at STP that could be produced from 7.45 g of propane. (10 points)

find V of CO2 at STP from

7.45 g of propane;

mol of propane = mass/MW = 7.45/44.1 = 0.16893 mol of propane

ratio is 1:3

0.16893 mol of --> 0.16893*3 = 0.50679 mol of CO2

1 mol at STP = 22.4 L

0.50679 mol --> 0.50679*22.4 = 11.35 L of CO2

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