Given the values of Hrxn, Srxn, and T below, determine Suniv. a) Hrxn= 90 kJ , S

Question

Given the values of Hrxn, Srxn, and T below, determine Suniv. a) Hrxn= 90 kJ , Srxn= 149 J/K , T= 297 K Suniv= BHrxn= 90 kJ , Srxn= 149 J/K , T= 754 K CHrxn= 90 kJ , Srxn= 149 J/K , T= 297 K DHrxn= 90 kJ , Srxn= 149 J/K , T= 403 K E) Predict whether or not the reaction in part A will be spontaneous. F) Predict whether or not the reaction in part B will be spontaneous. G) Predict whether or not the reaction in part C will be spontaneous. H)Predict whether or not the reaction in part D will be spontaneous.

Explanation / Answer

(a)

Ssys = 149 J/K

Hsys= 90 kJ

T= 297 K

Ssurr= - Hsys / T = - 90 / 297 = - 0.303 kJ/K = - 303 J/K

Suniv= Ssys + Ssurr = 149 - 303 = - 154 J/K

(b)

Ssys = 149 J/K

Hsys= 90 kJ

T= 754 K

Ssurr= - Hsys / T = - 90 / 754 = - 0.119 kJ/K = - 119J/K

Suniv= Ssys + Ssurr = 149 - 119= + 30 J/K

(c)

Ssys = - 149 J/K

Hsys= 90 kJ

T= 297 K

Ssurr= - Hsys / T = - 90 / 297 = - 0.303 kJ/K = - 303 J/K

Suniv= Ssys + Ssurr = - 149 - 303 = - 452J/K

(d)

Ssys = 149 J/K

Hsys= - 90 kJ

T= 403 K

Ssurr= - Hsys / T = 90 / 403 = 0.223 kJ/K = 223 J/K

Suniv= Ssys + Ssurr = 149 + 223 = 372 J/K

(e) Nonspontaneous

(f) Spontaneous

(g) Non spontaneous

(h) Spontaneous

NOTE: For a reaction to be spontaneous, deltaSuniv > 0

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