For 18.15 (d), is the compound in non-aromatic form because the sulfer is in sp3

Question

For 18.15 (d), is the compound in non-aromatic form because the sulfer is in sp3 formation? In order for a compound to be aromatic does each atom composing the ring need to be in sp2 form?

CTICE NH the lone pair are par o also the can cannot in case, th pairs this lone Not counted as because each atom in the count, This lone cannot be in with the p and therefore, have pair bond, p has pabta the double occupy aparbital. (if any) the skill 18.15 each of the following compounds determine which For ticipating in aromaticity N-H N. (e) (c) (d) (b)

Explanation / Answer

Ans: For a compound to be an Aromatic needs to be:

1. 4n+2 electrons (sp2 hybridized)

2. Planar (due to p-orbital overlapping)

Compound d is Thiazole which is aromatic although Sulphor atom is sp3 hybridized because the non bonding lone pair of electrons is involved in the - orbital overlap due to whihc it does contribute 4n+2 electrons along with planarity. Thus making it Aromatic.

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