The following questions concern the combustion reaction of ethane at 298 K: 2 C_
ID: 526176 • Letter: T
Question
Explanation / Answer
a. dH for the reaction is -ve, so the reaction is exothermic in nature
b. moles CO2 = 4.55/44 = 0.103 kmol
4 mol CO2 produced = -3119.7 kJ of heat,
so, 0.103 kmol CO2 would produce = 0.103 x 10^3 x -3119.7
= -321.33 kJ of heat
c. dHrxn = [(4 x 37.11 + 6 x 75.29) - (2 x 52.63 + 7 x 29.36)(398 - 298)]/1000 - 3119.7
= -3090.76 kJ at 398 K
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