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Na_3 PO_4 and Fe(C_2 H_3 O_2)_2 react in a double displacement reaction. a) Give

ID: 527598 • Letter: N

Question

Na_3 PO_4 and Fe(C_2 H_3 O_2)_2 react in a double displacement reaction. a) Give the complete balanced molecular equation. Be sure to assign state symbols. b) Write a full ionic equation for this reaction. Be sure it's still balanced, and don't forget state systems. c) Write a net ionic equation for this reaction. Again, check balance and state symbols. d) What are the spectator ions? ______and _____. Use the equation 3A + 2B rightarrow A_3 B_2 to answer the following question. a) 6 atoms of A can form how many A_3 B_2? 2A_3 B_2 b) 10 atoms of B can form how many A_3 B_2? 5A_3 B_2 c) 6 tons of A are reacted with 10 atoms of B. How many A_3 B_2 are formed? Which reactant is let over and how many of that reactant are left? What are the products of a neutralization reaction? Carbonic acid (H_2 CO_3) is not stable and decomposes into two molecules. What are those two molecules?

Explanation / Answer

12. (a) 2Na3PO4 (aq)+ 3Fe(C2H3O2)2 (aq)---> 6Na(C2H3O2) (aq)+ Fe3(PO4)2 (s)

(b) 6 Na+ (aq) + 2 PO42- (aq) + 3Fe2+ (aq) + 6 C2H3O2- (aq)   --->Fe3(PO4)2 (s) + 6 Na+ (aq) + 6 C2H3O2- (aq)

(c)  3Fe2+ (aq) + 2 PO42- (aq) ----> Fe3(PO4)2 (s)

(d) Spectator ions are Na+ and C2H3O2-, as they are present in both reactant and products.

16. (a) as 3 atoms of A reacts to form 1 molecule of A3B2

6 atoms of A reacts to form = 6 *1/3 = 2 molecule of A3B2

(b) as 2 atoms of B reacts to form 1 molecule of A3B2

10 atoms of B reacts to form = 10 *1/2 = 5 molecule of A3B2

(c) as 3 atoms of A reacts to form 2 atoms of B

6 atoms of A reacts to form = 6 *2/3 = 4 atoms of B

thus atom B will be left unreacted and 6 atoms of B will left after reaction is complete

19. netralization reaction occurs between and acid (HA) and base (BOH)

HA + BOH -----> AB + H2O

20. carbonic acid decomposes to form CO2 and H2O