A tertiary halide is most likely to react with NaOH by which mechanism? a) S_n 2

Question

A tertiary halide is most likely to react with NaOH by which mechanism? a) S_n 2 b) S_n 1 c) E_2 The mechanism shown here is for an: (Ph = phenyl an aromatic ring) a) E_2 reaction b) S_n2 reaction c) S_n1 reaction A primary halide is most likely to react with NaOH by which mechanism? a) E_2 b) S_N1 c) S_n2 6 A tertiary halide is most likely to react with H_2 O by which mechanism? a) E_2 b) S_N1 c) S_n2 Which solvent is best for S_N 2 reactions? a) CH_3 OH b) DMSO c) HBr d) H_2O The leaving group and the H on the adjoining carbon must be anti periplanar to each other in which mechanism? a) S_n2 b) S_N1 c) E_2 An S_n2 reaction goes with: a) inversion b) racemization c) retention d) rotation The first slow step in an S_N1 reaction is: a) attack by nucleophile/base b) loss of H+ c) loss of leaving group d) protonation of nucleophile/base Zaitsev's Rule says a) in the presence of a strong nucleophile substitution is favored over elimination b) the H go

Explanation / Answer

question 2 Answer = The product generated is 4-(2-methyl benzene) Toluene

their is formation of carbon-carbon bond of , bromine carbon and boron carbon of both aromatic rings.

Question .No Answer 3 b - SN1 4 a -E2 5 c-SN2 6 C-SN2 7 B-DMSO 8 c-E2 9 a-inversion 10 c-loss of leaving group 11 C-most substituted alkene is favour

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