The rate law for the chemical reaction 5Br (aq) + BrO_3^-(aq) + 6H^+(aq) rightar
ID: 527790 • Letter: T
Question
The rate law for the chemical reaction 5Br (aq) + BrO_3^-(aq) + 6H^+(aq) rightarrow 3Bf_2(aq) + 3H_2O(I) has been determined experimentally to be Rate -K[Br][BrO_3^-][H^+]^2. What is the overall order of the reaction? 3 2 4 1 5 The solubility of CaSO_4 in pure water at 0 degree is 1.00 g/L. What is the value of the solubility product? 1.00 times 10^-3 8.57 times 10^2 7.35 times 10^-3 5.40 times 10^-3 For the reaction 2Hl(g) H_2(g) + I_2(g) K_c = 0.290 at K. If the initial concentrations of H1, H_2, and I_2 are all 1.50 times 10^-3 M at 400 K, which one of the following statements is correct? The concentrations H_2 and l_2 will increase as the system is approaching equilibrium. The concentrations of HI and l_2 will increase as the system is approaching equilibrium The concentration of HI will increase as the system is approaching equilibrium. The concentration of H_2 and HI will decreases as the system is approaching equilibrium. The system is at equilibrium. The half-life of reaction is the time it takes for the reactant concentration to decreases to on-half of its initial value one-half of the times the reaction will take to go to completion. The time it takes for the amount of product formed to equal half the initial amount of reactant. how long the reaction can run before stopping. twice as long for a second-order reaction as it is for a first-order reaction. What is the hydroxide ion concentration of a saturated solution of Mg(OH)_2? For Mg(OH)_2, K_p = 1.8 times 10^-11 1.0 times 10^-3 M 1.0 times 10^-3 M 4.2 times 10^-6 M 1.7 TIMES 10^-4 M 3.3 times 10^-4 M.Explanation / Answer
Ans 41 . C) 4
The order of the reaction is the sum of coefficients of elementary reaction , but this is not always true for complex reactions such as one given in the reaction .
So here the order of the reaction can be calculated by adding the powers of reactant entities in the rate law , which is 1 + 1+ 2 = 4
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