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In spite of the high equilibrium constant (K = 10^25) for the reaction given her

ID: 527804 • Letter: I

Question

In spite of the high equilibrium constant (K = 10^25) for the reaction given here, the reaction proceeds very slowly, reaching equilibrium only after several days at room temperature. [Co(NH_3)_6]^3+ + 6H_3O^+ [Co(H_2O)_6]^3+ + 6NH_4^+ This observation is consistent with the activation energy for the forward reaction being low. the classification of (Co(NH_3)_6]^3+ as an inert complex. [Co(NH_3)_6]^3+ being more labile than [Co(H_2O)_6]^3+. [Co(NH_3)_6]^3+ being unstable in strong acid. The major reason that [Ni(H_2NC_2CH_2NH_2)_3]2+ is thermodynamically more stable than [Ni(NH_3)_6]^2+ is the chelate effect. greater Lewis basicity of H_2NCH_2CH_2NH_2, compared to two NH_3, ligands. macrocyclic effect. relative rates of their formation. The chromium product of the redox reaction of [Co(NH_3)_5CI]^2+ with [Cr(H_2O)_6]^2+ is [Cr(H_2O)_5Cl]^2+. This demonstrates that the reaction proceeds by a process in which a chloride ligand is lost from the Co(III) center before association with the Cr(III) species and before electron transfer. a Co(III)-bound chloride ligand enters the coordination sphere of the Cr(II) species before electron transfer. a free chloride ion replaces H_2O in [Cr(H_2O)_6]^2+ after electron transfer. the inner coordination spheres of both reactants remain intact during electron transfer. Which is mot isoelectronic with [B_12H_12]^2-? [AIB_11H_12]^2- [NB_11H_12]^2- [CB_11H_12]^- [C_2B_10H_12] Which is an acidic oxide? B_2O_3 BaO MgO Na_2O

Explanation / Answer

(38) (B)

(39) (A) Because ehtylene diamine is bidentate ligand which can form chelate with the cental metal ion.

(40) (D)

(41) [B12H12]2- (74 e) is not isoelectronic with (B) [NB11H12]2- (76 e)
(42) (A)

B2O3 is an acidic oxide.

B2O3 + 3 H2O -----------> 2 H3BO3

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