10. Use the data below to find the standard free energy change for the reaction:
ID: 527943 • Letter: 1
Question
10.
Use the data below to find the standard free energy change for the reaction:
CS2 (g ) + 3Cl2 (g ) CCl4 (g) + S2Cl2 (g)
Compound
DfH° / kJmol-1
DfG° / kJmol-1
S° / Jmol-1K-1
CCl4(l)
–128.2
–62.5
214.4
CCl4(g)
–58.2
309.7
CS2(l)
89.70
65.27
151.34
CS2(g)
116.9
66.8
238.0
S2Cl2(l)
–59.4
—
—
S2Cl2(g)
–19.50
–29.25
319.45
Cl2(g)
-
-
223.1
Also find the missing deltafH for CCl4 (g ).
Compound
DfH° / kJmol-1
DfG° / kJmol-1
S° / Jmol-1K-1
CCl4(l)
–128.2
–62.5
214.4
CCl4(g)
–58.2
309.7
CS2(l)
89.70
65.27
151.34
CS2(g)
116.9
66.8
238.0
S2Cl2(l)
–59.4
—
—
S2Cl2(g)
–19.50
–29.25
319.45
Cl2(g)
-
-
223.1
Explanation / Answer
CS2 (g ) + 3Cl2 (g ) CCl4 (g) + S2Cl2 (g)
dG = Gproducts - dGreactants
dG = (-58.2 + -29.25) - (66.8 + 3*0)
dG = -154.25 kJ
Q2.
find missing dH
dG = dH - T*dS
-58.2 = dH - 298*(309.7/1000)
dH = -58.2+298*(309.7/1000)
dH = 34.0906 kJ
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