This worksheet is due on 5/10/2017. There will be no exceptions. It will be chec

Question

This worksheet is due on 5/10/2017. There will be no exceptions. It will be checked so do your work as accurately as possible. If the sheet is complete with all work included, it will be worth 7 points on the final exam. Let me know if you have any questions. Please do the problems on another piece of paper. 1. What would the air pressure need to be (g ve a specific numerical in value) order for water to boil at room temperature? Explain how you determined your answer. (Hint: look up the definition of boiling point. 2. As gas molecules are added to a rigid container, would the temperature need to be increased, decreased, or unchanged in order to keep the pressure constant? plain using only kinetic-molecular theory. CThat means do not use any equations.) 3. Consider the following chemical reaction: 2 NO20g) 7 H20g) 2 NH,(g) 4 H2O(g) If 54.67 liters of hydrogen are used up (measured at 288 oC and 1.39 atm) then what volume of water vapor is produced (measured at the same temperature and pressure) 4. a. You have a sample of a gaseous compound which has a density of 7.11 kg/m3 at 58 oc and 82.2 kPa. What is the molar mass of this gas? b. This same gas sample is (by mass) 20.2% Cand 79.8 F. Find the empirical formula of the compound. c. What is the molecular formula ofthis compound? 5. a. A sample of neon gas occupies 725 mL at 635 torr. What will the pressure be if the volume is expanded to 8.00 L at the same temperature? b. A sample of carbon dioxide gas occupies 12.37 liters at 544 kPa and 28.44 °C. At what temperature (oC) will the carbon dioxide occupy 31.44 liters if the pressure changes to 3.000 atm?

Explanation / Answer

Q1.

The pressure we need for T = 25°C, is about 23.8 torr, or 23.8mm Hg

Q2.

if moles of gas increases, then

T1/n1 = T2/n2

according to this ratio, if n2 increases, then T2 must increase as well in order to avoid P changes

Q3.

ratio is:

7 Liters of H2 = 4 Liters of H2O

so

54.67 L --> 4/7 * 54.67 = 31.24 L of H2O expected

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