The K_eq for the equilibrium below is 0.112 at 700.0 degree C. SO_2(g) + 1/2 O_2

Question

The K_eq for the equilibrium below is 0.112 at 700.0 degree C. SO_2(g) + 1/2 O_2(g) SO_3(g) What is the value of K_eq at this temperature for the reaction? SO_3(g) SO_2(g) + 1/2O_2(g) A) 0.224 B) 0.0125 C) 0.112 D) 8.93 E) -0.112 Consider the following reaction at equilibrium, . 2 CO_2 (g) 2CO(g) + O_2(g) delta H degree = -514 kJ lessthanorequalto Chatelier's principle predicts that the equilibrium partial pressure of CO(g) can be maximized by carrying out the reaction _____ A) at high temperature and high pressure B) at high temperature and low pressure C) at low temperature and low pressure D) at low temperature and high pressure E) in the presence of solid carbon The K_a of hydrazoic acid (HN_3) s 1.9 times 10^-5 at 25.0 degree C. What is the pH of a 0.35 M aqueous solution HN_3? A) 1.14 B) 2.41 C) 5.23 D) 2.59 E) -2.46 Of the following equilibria, only _____ will shift to the left in response to a decrease in volume. A) H_2(g) + Cl_2(g) 2HCl(g) B) 2SO_3(g) 2SO_2(g) + O_2(g) C) N_2(g) + 3H_2 2NH_3(g) D) 4Fe(s) + 3O_2(g) 2Fe_2O_3(s) E) 2HI(g) H_2(g) + I_2(g) Calculate the pH of 0.726 M anilinium hydrochloride (C_6H_5BH_3Cl) solution in water, given that K_b aniline is 3.83 times 10^-4 A) 1.77 B) 12.2 C) 5.36 D) 8.64 E) 12.4 A Bronsted-Lowry base is defined as a substance that _____ A) increases [H+] when placed in H_2O B) decreases [H+] when placed in H_2O C) increases [OH^-] placed in H_2O D) acts as a proton acceptor E) acts as a proton donor For which salt should the aqueous solubility be most sensitive to pH? A) Ca (NO_3)_2, B) CaF_2 C) CaCl_2 D) CaBr_2 E) Cal_2 The magnitude of K_w indicates that _____ A) water autoionizes very slowly B) water autoionizes very quickly C) water autoionizes only to a very small extent D) the autoionization of water is exothermic What is the molar solubility of barium fluoride (BaF_2) in water? The solubility-product constant for is 1.7 omega 10^-6 at 25 degree C. A) 6.5 times 10^-4 B) 1.2 times 10^-2 C) 1.8 times 10^-3 D) 7.5 times 10^-7 E) 5.7 times 10^-7 The hydride ion, H^-, is a stronger base than the hydroxide ion, OH^-. The product(s) of the reaction

Explanation / Answer

Q15.

original reaction

SO2 + 1/2O2 = SO3

the new equation

SO3 = SO2 + 1/2O2

clearlyt, it is only inverted

so

Koriginal = [SO3] / [SO2][O2]^0.5

Knew =  [SO2][O2]^0.5 / [SO3]

ratio between Koriginal and Knew

Knew = 1/Koriginal = 1/(0.112) = 8.9285

choose D

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