A spontaneous process: will happen quickly. releases large amounts of energy. re
ID: 528926 • Letter: A
Question
A spontaneous process: will happen quickly. releases large amounts of energy. requires an external action in order to begin reacting. will continue on its own once begun. is never endothermic. Which of the following has the highest entropy? 1 mol of liquid water at 30 degree C an amount of l.0M aqueous NaCl solution containing 1 total mol of ions & molecules at 30 degree C 1 mole of water vapour at 30 degree C 1 mole of ice at -10 degree C 1 mole of water under 10 atm of pressure at -10 degree C Consider the process whereby 1.00 mol of H_2O(s) is melted to H_2O(I) at the normal melting point of ice, 273.15 K. Which of the following is true for this process? Delta H > 0 delta G = 0 delta H = T delta S All of these are true. None of these is true. Which is the best estimate for the boiling point of benzene given that delta H degree of vaporization is 31 kJ/mol and delta S degree of vaporization is 90 J/(mol K). 5 degree C 15 degree C 30 degree C 50 degree C 70 degree C The following reaction has...2 N_2O(g) rightarrow 2 N_2 (g) + O_2(g) a negative delta H and a negative delta S a positive delta H and a negative delta S a negative delta H and a positive delta S a positive delta H and a positive delta S It is not possible to determine without more information. What is the value of Keq at 25 degree C for a reaction, if the value of delta G degree rxn is -47.8 kJ at 25 degree C? 1.70 6.88 2.30 times 10^-2 2.74 times 10^-5 2.37 times 10^-8 If the equilibrium constants for the two reactions 2 HCl()g) Ba H_2(g) + Cl_2(g) and I_2(g) + Cl_2(g) Ba 2ICl(g) are denoted K_1 and K_2 respectively, find the equilibrium constant for the reaction 2 HCl(g) + I_2(g) Ba 2ICl(g) + H_2(g) Keq = (K_1/K_2)^2 ()K_1 *K_2)^2 K_1 *K_2 K_1 +K_2 K_1*K_2/2Explanation / Answer
8) - A) Will happen quickly.
9) - D) 1 mole of ice aat -10 degree celsius.
10) - D) All of these are true.
11) - B) 15
12) -C) A negative delta H and positive delta S.
13) - D) 2.74*10^5
14) -A) (K1/K2)^2
12) - C)
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