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Question

C fi 8 https://session.masteringchemistry.com/myct/itemview?assignmentProblemID 82717743 Apps D Mydwu YouTube T Expert TA Login user Dashboard Netnix G Coogle D sign In Chem 182.001 General Chemistry II S17 Brown 12.67 previous 10 of Exercise 12.67 How much heat on kJ) is required to warm 13.0gofice, initially at-110 C,to steam at 114.0°C? The heat capacity of o is 200 J/g Cand that of steam is 201 J/g eC. Submit Mr Ansnemo up Incorrect: Try Again: 4 attempts remaining Provide Eendback C MacBook Pro

Explanation / Answer

Q = heat change for conversion of ice at -11 oC to ice at 0 oC + heat change for conversion of ice at 0oC to water at 0oC + heat change for conversion of water at 0oC to water at 100 oC +heat change for conversion of water at 100 oC to vapour at 100 oC+ heat change for conversion of vapour at 100 oC to vapour at 114 oC

Amount of heat absorbed , Q = mcdt + mL + mc'dt + mL' + mc"dt"

                                              = m(cdt + L + c'dt' + L' + c"dt" )

Where

m = mass of water = 13.0 g

c” = Specific heat of steam = 2.01 J/g degree C

c' = Specific heat of water = 4.186 J/g degree C

c = Specific heat of ice= 2.09 J/g degree C

L’ = Heat of Vaporization of water = 2260 J/g

L= Heat of fusion of ice = 334.9 J/g

dt’’ = 114-100 = 14oC

dt' = 100 -0 =100 oC

dt = 0-(-11)=11 oC

Plug the values we get Q = m(cdt + L + c'dt '+ L' + c"dt" )

= 3.065x103 J

= 3.065 kJ