Part A A cylinder with a moveable piston contains 0.90 mol of gas and has a volu

Question

Part A

A cylinder with a moveable piston contains 0.90 mol of gas and has a volume of 343 mL .

What will its volume be if an additional 0.22 mol of gas is added to the cylinder? (Assume constant temperature and pressure). Express your answer using two significant figures.

[ V2= ] mL

Part B

A sample of nitrogen gas in a 1.58-L container exerts a pressure of 1.17 atm at 28 C .

What is the pressure if the volume of the container is maintained constant and the temperature is raised to 356 C?

[ P =   ] atm

Part C

A sample of gas has a mass of 0.560 g . Its volume is 118 mL at a temperature of 85 C and a pressure of 752 mmHg .

Find the molar mass of the gas.

[      ] g/mol

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Part D

Calculate the root mean square velocity and kinetic energy of CO , CO2 , and SO3 at 272 K .

Calculate the root mean square velocity of CO at 272 K .

U_rms = [     ] m/s

Part E

Calculate the root mean square velocity of CO2 at 272 K .

U_rms = [     ] m/s

Part F

Calculate the root mean square velocity of SO3 at 272 K .

U_rms = [     ] m/s

Part G

Calculate the kinetic energy of CO at 272 K .

E_avg = [     ] J/mol

Part H

Calculate the kinetic energy of CO_2 at 272 K .

E_avg = [     ] J/mol

Part I

Calculate the kinetic energy of SO3 at 272 K .

E_avg = [     ] J/mol

Part J

Which gas has the greatest velocity?

A. CO, B. CO_2, C. SO_3, or D. all molecules have the same velocity

Part K

The greatest kinetic energy?

A. CO, B. CO_2, C. SO_3, or D. all molecules have the same kinetic energy

Part L

The greatest effusion rate?

A. CO, B. CO_2, C. SO_3, or D. all molecules have the same rate

I kow this is a lot, but I would really appreciate any assistance!

Explanation / Answer

A)

Given:

Vi = 343 mL

ni = 0.90 mol

nf = 0.90 + 0.22 = 1.12 mol

use:

Vi/ni = Vf/nf

343 mL / 0.90 mol = Vf / 1.12 mol

Vf = 427 mL

Answer: 427 mL

B)

Given:

Pi = 1.17 atm

Ti= 28.0 oC = (28.0+273) K = 301 K

Tf= 356.0 oC = (356.0+273) K = 629.0 K

use:

Pi/Ti = Pf/Tf

1.17 atm / 301 K = Pf / 629 K

Pf = 2.45 atm

Answer: 2.45 atm

C)

1st find the number of mol

Given:

P= 752.0 mm Hg = (752.0/760) atm = 0.989 atm

V= 118.0 mL = (118.0/1000) L = 0.118 L

T = 85.0 oC = (85.0+273) K = 358 K

use:

P * V = n*R*T

0.989 atm * 0.118 L = n * 0.0821 atm.L/mol.K * 358.0 K

n = 3.972*10^-3 mol

now use:

n = mass / molar mass

3.972*10^-3 mol = 0.560 g/ MM

MM = 141 g/mol

Answer: 141 g/mol

I am allowed to answer only 1 question at a time

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