The concentration dependence of the osmotic pressure of solutions of a macromole
ID: 530521 • Letter: T
Question
The concentration dependence of the osmotic pressure of solutions of a macromolecule at 20 degree C was found to be as follows: Determine the molar mass of the macromolecule. Calculate the osmotic pressure exhibited by a 0.10M sucrose solution at 20 oC. Calculate the osmotic pressure exhibited by a 0.42M KOH solution at 30 oC. You add 1 .00 kg of ethylene glycol (C_2H_6O_2) antifreeze to your car radiator which contains 4450 g of water. What are the boiling and freezing points of the solution? What is the freezing point of 0. 11 1 m urea in water? What is the boiling point of 0.200 m lactose in water? The boiling point of ethanol (C_2H_5OH) is 78.5 degree C. What is the boiling point of a solution of 3.4 g of vanillin (M = 152.14 g/mol) in 50.0 g of ethanol (K_b of ethanol = 1.22 degree C/m)? The freezing point of benzene is 5.5 degree C. What is the freezing point of a solution of 5.0 g of naphthalene (C_10H_8) in 444 g of benzene (K_f of benzene = 4.90 degree C/m)?Explanation / Answer
5) osmotic pressure = iMRT
i = 1
M = 0.1 M
R = gas constant
T = 273 + 20 = 293 K
we get,
osmotic pressure = 1 x 0.1 x 0.08205 x 293 = 2.40 atm
6) osmotic pressure = iMRT
i = 2
M = 0.42 M
R = gas constant
T = 273 + 30 = 303 K
we get,
osmotic pressure = 2 x 0.42 x 0.08205 x 303 = 20.88 atm
7) molality = 1000 g/62.07 g/mol x 4.450 = 3.62 m
Boiling point = 100 + iKbm
= 100 + 1 x 0.512 x 3.62
= 101.85 oC
Freezing point = 0 - iKfm
= 0 - 1 x 1.86 x 3.62
= -6.73 oC
8) Freesing point = 0 - iKfm
= 0 - 1 x 1.86 x 0.111
= -0.206 oC
9) Boiling point = 100 + iKbm
= 100 + 1 x 0.512 x 0.2
= 100.10 oC
10) Boiling point = 78.5 + iKbm
= 78.5 + 1 x 1.22 x 3.4/152.14 x 0.05
= 100.55 oC
11) freexing point = 5.5 - iKfm
= 5.5 - 1 x 5 x 4.90/128.17 x 0.444
= 5.07 oC
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