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(Figure 1) Part A Begin by calculating the number of atoms in the sun. Assume th

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Question

(Figure 1)

Part A

Begin by calculating the number of atoms in the sun. Assume that the sun is pure hydrogen with a density of 1.4 g/cm3 . The radius of the sun is 7×108m and the volume of a sphere is given by V=43r3 .

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Part B

Since the sun is an average-sized star, and since stars are believed to compose most of the mass of the visible universe (planets are so small they can be ignored), we can estimate the number of atoms in a galaxy by assuming that every star in the galaxy has the same number of atoms as our sun. The Milky Way galaxy is believed to contain 1×1011 stars. Use your answer from previous part to calculate the number of atoms in the Milky Way galaxy.

Since the sun is an average-sized star, and since stars are believed to compose most of the mass of the visible universe (planets are so small they can be ignored), we can estimate the number of atoms in a galaxy by assuming that every star in the galaxy has the same number of atoms as our sun. The Milky Way galaxy is believed to contain 1 imes 10^{11} stars. Use your answer from previous part to calculate the number of atoms in the Milky Way galaxy.

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Part C

The universe is estimated to contain approximately 1×1011 galaxies. If each of these galaxies contains the same number of atoms as the Milky Way galaxy, what is the total number of atoms in the universe?

The universe is estimated to contain approximately 1 imes 10^{11} galaxies. If each of these galaxies contains the same number of atoms as the Milky Way galaxy, what is the total number of atoms in the universe?

Our sun is one of the 100 billion stars in the Milky Way galaxy. The universe is estimated to contain about 100 billion galaxies.
You can use the concepts in chapter 6 in textbook to obtain an estimate of the number of atoms in the universe. The following steps will guide you through this calculation.

(Figure 1)

Part A

Begin by calculating the number of atoms in the sun. Assume that the sun is pure hydrogen with a density of 1.4 g/cm3 . The radius of the sun is 7×108m and the volume of a sphere is given by V=43r3 .

Begin by calculating the number of atoms in the sun. Assume that the sun is pure hydrogen with a density of 1.4 { m g/cm^3}. The radius of the sun is 7 imes 10^8 { m m} and the volume of a sphere is given by { m V} = { extstyle{4 over 3}}pi { m r^3}.

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Part B

Since the sun is an average-sized star, and since stars are believed to compose most of the mass of the visible universe (planets are so small they can be ignored), we can estimate the number of atoms in a galaxy by assuming that every star in the galaxy has the same number of atoms as our sun. The Milky Way galaxy is believed to contain 1×1011 stars. Use your answer from previous part to calculate the number of atoms in the Milky Way galaxy.

Since the sun is an average-sized star, and since stars are believed to compose most of the mass of the visible universe (planets are so small they can be ignored), we can estimate the number of atoms in a galaxy by assuming that every star in the galaxy has the same number of atoms as our sun. The Milky Way galaxy is believed to contain 1 imes 10^{11} stars. Use your answer from previous part to calculate the number of atoms in the Milky Way galaxy.

About 1053 atoms. About 1023 atoms. About 1057 atoms. About 1068 atoms.

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Part C

The universe is estimated to contain approximately 1×1011 galaxies. If each of these galaxies contains the same number of atoms as the Milky Way galaxy, what is the total number of atoms in the universe?

The universe is estimated to contain approximately 1 imes 10^{11} galaxies. If each of these galaxies contains the same number of atoms as the Milky Way galaxy, what is the total number of atoms in the universe?

About 1070 atoms. About 1068 atoms. About 1040 atoms. About 1034 atoms. About 10100 atoms. About 1093 atoms. About 1079 atoms. About 1059 atoms.

Explanation / Answer

Part A)

Volume = (4/3)pir^3

feeding r value,

Volume = 4 x 3.14 (7 x 10^8 x 100)^3/3

             = 1.43 x 10^33 cm^3

Grams = 1.43 x 10^33 cm^3 x 1.4 g/cm^3 = 2.00 x 10^33 g

number of atoms = 2 x 10^33 x 6.023 x 10^23/2 = 6.02 x 10^56 atoms

Part B)

Number of atoms in a galaxy = 1 x 10^11 x 6.02 x 10^56 = 0.602 x 10^68 atoms

Answer : 10^68

Part C) number of atoms in universe = 0.602 x 10^68 x 1 x 10^11 = 0.602 x 10^79 atoms

Answrr : 10^79 atoms

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