Question 12 of 30 Map Sapling Learning At a certain temperature, 0.840 mol of SO

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Question 12 of 30 Map Sapling Learning At a certain temperature, 0.840 mol of SO3 is placed in a 4.00-L container At equilibrium, o.170 mol of O2 is present. Calculate Kc. Number Previous 8 Give Up & View solution Check Answer 0 ext Exi Hint Due Date: 5121/20170 Points Possible: 30 Grade Category: Graded Description Policies Homework You can check your answers. You can view solutions when yo up on any question, You can keep trying to answer you get it right or give up. You lose 5% of the points avail in your question for each inco Textbook o Help with This Topic O Web Help & Videos o Technical support and Bug

Explanation / Answer

The reaction is as follows:

2SO3 <------> 2SO2 + O2

Kc at equilibrium = [O2]*[SO2]^2/[SO3]^2

given O2 at equilibrium = 0.17
Moles of SO2 FORMED = 2*(0.17)=0.34 MOL

concentration of SO2 =0.34 mol/ 4 L=0.085 M

Moles of SO3 LEFT when the system /reaction reached equilibrium = 0.84-2*0.17=0.5 mol=0.5/4=0.125 M

Thus the concentration of SO3 at equiibrium is 0.125 M

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THUS, Kc =[0.17]*[0.085]^2/0.125^2=7.8*10^-2



so no. of moles of SO2 at eq = 2x = 2X0.16 = 0.32
no. of moles of SO3 = 0.76-2x = 0.76-0.32 = 0.44

[SO3] = eq. conc. of SO3 = 0.44/3.5 = 0.126 M
[SO2] = 0.32/3.5 = 0.092 M
[O2] = 0.16/3.5 = 0.046 M

Kc = [SO2]^2 [O2] / [SO3]^2

Kc = 0.092^2 X 0.046 / 0.126^2

Kc = 8.464 X 10^-3 X 0.046 / 0.016

Kc = 3.893 X 10^-4 / 0.016 = 0.024

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