Using the periodic of elements, determine the molar mass for this molecule. (A).
ID: 530995 • Letter: U
Question
Using the periodic of elements, determine the molar mass for this molecule. (A). The numbers of atoms for chlorine is 2 and the numbers of atoms for Calcium is 1. (B). Chlorine atomic m is 35.453 and Calcium atomic mass is 40.078. So therefore 40.078 + 35.453 * 2 = 110.984 g/mol You are asked to calculate the concentration of a NaCl (in water) solution in several ways and are given the following information: 25 g NaCl, 500 mL solution, Molecular weight of NaCl = 58.44 g/mole. Students must for parts a and b. (a) Calculate the mass/volume percent concentration. (b) Calculate the molarity of the solution. What volume (L) of a 1.5 KOH solution can be prepared by diluting 0.2 L of a 5M KOH solution? Show your work. 51 *5M = 2.5 mol, 2m5mol/3M = .833LExplanation / Answer
Q8.
m = 25 g of NaCl
V = 500 mL
a)
mass/volume % --> mass of NaCl / total Volume * 100% = 25/500*100 = 5% m/v of NaCl
b)
Molarity = mol / Volume in liters
mol = mass/MW = 25/58.44 = 0.427789 mol
M = 0.427789/0.5 = 0.855578 M of NaCl
Q9
V of 1.5 M opf KOH
Apply Dilution law
M1*V1 = M2*V2
1.5*V1 = 0.2*5
V1 = 0.2*5/1.5
V1 = 0.66666 L = 666.67 mL
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