im having a hard time constructing the original formula for this question please

Question

im having a hard time constructing the original formula for this question please help me with clear explanation

Half Reaction Ag (aq) e Ag(s) AgBr(s) e Ag (s) Br (aq) Aus (aq) 3e- Au(s) Br2(l) 2e- 2 Br (aq) Cl (g) 2e 2 Cl (aq) Ca (aq) 2e Ca (s) Cos (aq) e Co (aq) 2+ 2e Co (s) Co (aq) Cu (aq) e- Cu(s) Cu (a 2e- Cu(s) Fe (aq) 2 Fe(s) 2+, Fes (aq) e Fe Caq0 Fe(CN)6 (aq) e- Fe(CN)6 (aq0 2H20 (l) 2 e- H2(g) 2 OH 2+, Hg2 (aq) 2e- 2 Hg(l) Hg2Cl2(s) 2e- 2 Hg(l) 2 Cl (aq) Hg2SO4 (s) 2e 2 Hg(l) SO4 (aq) K (aq) e K(s) Na (aq) er Na(s) Ni2 (aq) 2 e Ni(s) Sn (aq) Sn (aq) 2 e Sna (aq) zna (aq) 2 e- Zn(s) +0.799V +0.07V +1.50 V +1.09 V +1.358 V -2.868 V +1.82 V -0.28 V +0.520 V +0.340V -0.44 V +0.771 V +0.361V 0.000V -0.83V +0.796 V +0.268 V +0.616 V -2.931 V 2.71 V -0.257 V -0.138 V +0.13 V -0.763 V

Explanation / Answer

7.The name of solid Hg2Cl2 is mercury(I) chloride.

Therefore option (d) is correct.

8.Eocell = Eocathode - Roanoke

=Eo Hg22+/Hg -Eo CO2+/Co

= +0.796 -(-0.28)

= +1.076V

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