please show work clearly for the math part HO polarimeter tube. The rotation was

Question

please show work clearly for the math part

HO polarimeter tube. The rotation was found to be 10.00 when measured at 24 oC What is CH H3C H H the enantiomeric excess of this sample (closest value)? +100 g) ow many mg of Phorbol are present O' HO the sample? OH iii. Stylopine f) A 1500.0 mg sample of Stylopine and its enantiomer was dissolved in a solution with a 25 volume of 6.00 ml and placed in a 5.00 cm 300 polarimeter tube. The rotation was found to be +6.000 when measured at 25 oC. What is the enantiomeric excess of this sample (closest value)? g) How many mg of Stylopine are present in the sample? Copyright O D. T. Whitaker, PhD, Henry Ford Community College

Explanation / Answer

A) with specific rotation of pure enantiomer -100 degree for other enantiomer

enantiomeric excess = -10 x 100/-100 = 10%

so we have 10 + 90/2 = 55% of major enantiomer (of total mixture)

and, 45% of other enantiomer (of total mixture)

B) concentration of solution = 1.5 g/6 ml = 0.25 g/ml

specific rotation of pure enentiomer = +300 degree

enantiomeric excess = +6 x 100/+300 = 2%

So we have 2 + 98/2 = 51% of major enantiomer

49% of minor enentiomer in the mixture

g) mg of stylopine present = 0.51 x 1.5 x 1000 = 765 mg

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