Question 3 What is the standard free energy change at 298K for the equilibrium r

Question

Question 3 What is the standard free energy change at 298K for the equilibrium reaction that describes how acetic acid dissociates in water (also known as the acid dissociation constant-equation)? Ka 1.8x10 at 29 Enter in kJ, Don't use scientific notation, and don't type in the units. Question 4 2NH303) CO2lg) NH2 CONH2(aa) H20 AG 298 13.2 kJ What is the value of AG when you have 298 o.14 atm NH3, 5.24 atm CO2, 1.5M NH2CONH2 Enter in kJ, Don't use scientific notation, and don't type in the units. 1 pts 1 pts

Explanation / Answer

We know,

delta G = delta Go + RT ln Q

so  delta G (298K) = delta Go(298 K) + RT ln Q

where R=gas constant 8.31 J/mol K and T is temperature in Kelvin

where Q=[NH2CONH2]/[CO2][NH3]2=1.5/5.24 x (0.14)2=14.60

then, ln Q= 2.68

delta G (298K) = -13.2 kJ + RT ln Q= -13.2 kJ + 8.31 x 298 x 14.60 x 0.001

= -13.2 kJ + 36.2 kJ= 23.0 kJ

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