2.) in preparing the KHP solution, a student did find a 100 mL volumetric flask

Question

2.) in preparing the KHP solution, a student did find a 100 mL volumetric flask and instead used a 200 mL size to dissolve the same weight of solid to be dissolved in 100 mL solution. In comparison to preparing a 100 mL solution as described in the procedure, explain how the student's action will affect (if any):
A.) the number of moles of KHP in a 25.00 mL aliquot of the solution
B.) the equivalence point of the titration

C.) the stoichiometry of the reaction?

2) In preparing the KHP solution, student did find a 100 ml volumetric and instead used a 200 mL size com the same wei of solid the n to preparing a 100 mL as in student's action will affect (if any): described in the procedure, explainhow a) The number of moles of KHP in a 25.00 mL aliquot of the solution. b) The equivalence point of the titration? c) The stoichiometry of the reaction?

Explanation / Answer

answer=>standard solution prepartion always use fix size of volumetric whch are made on ISO standard value.so uncertainity reduce. deviation less,,

comparison of both we prepare two solution of KHP in 100 ml and 200 ml and we find out difference in both of them.

solution preparation=> weight is not given (if given in your priveous, either in standartion, use providede weight at the weight position ,method always same only value change),so we use 1 mole weight of KHP=

molar mass of KHP =204.22 gm mol-1, and dissolve in 200 ml ....now we find out concencentration of solution

molarity ==> 204.22x1000/204.22x200 ===> also written 1 molex1000/200 ml===> 5 M

now if we take in 100 ml than molarity ====> 1mole x1000/100 ===>10 M

difference becomes twice both of them solution..

1.... we use 25 ml aliquot than no. of mole ==> 5 MX 25 ml = 125 milimole

we use 10 M (which make in 100ml than ) 25 ml aliquot than ===> 10M x25 ===>250 milimole

2...

equivalent point both have same mole we also use equation for equality===>

KHP SIDE C1V1==C2V2 NAOH SIDE EXAMPLE= 5 M X25 ML == C2 XV2 ===>125 MILMOLE BOTH SIDE

3...stichiometry

KHC8H4O4 + NaOH H2O + NaKC8H4O4

Mole ratio = 1 KHP: 1NaOH

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