Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Experimental Chemistry I Part II: Heat of Neutralization of Acids Data Tables 2:

ID: 532794 • Letter: E

Question

Experimental Chemistry I Part II: Heat of Neutralization of Acids Data Tables 2: Heat of Neutralization of HCI Trial 2 Trial 1 Heat capacity of the calorimeter (Average value O. 2 NaOH concentration (mol/L HCl concentration (mol/L) Initial NaOH temperature (O 222 22 G Initial HC1 temperature ZZS 22.2 (O 27. S 22 Average initial temperature Final temperature (C au S so s ES Temperature change eC) Mass of solution (g) Heat of neutralization U) Moles of HCl neutralized (mol) Molar heat of neutralization (J/mol Average molar heat of neutralization (/mol) Data Tables 3: Heat of Neutralization of HC2H3O2

Explanation / Answer

From the given data

Trial 1

heat of neutralization = 103.1241 x 4.18 (6.75) + 19.84 x 6.75 = 3043.57 J

moles HCl = 0.9805 M x (103.1241/2 x 1000) = 0.0516 mols

molar heat of neutralization = = 3043.57/0.0516 x 1000 = 58.98 kJ/mol

Trial 2

heat of neutralization = 103.7452 x 4.18 (5.65) + 19.84 x 5.65 = 2562.25 J

moles HCl = 0.9805 M x (103.7452/2 x 1000) = 0.051 mols

molar heat of neutralization = 2562.25/0.051 x 1000 = 50.38 kJ/mol

Average molar heat of neutralization = 54.68 kJ/mol

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote