Can you answer the following questions with work, please? A) The conversion of g

Question

Can you answer the following questions with work, please?

A) The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Glucose-6-phosphate was mixed with the enzyme under standard conditions and the reactions was allowed to come to equilibrium. If the keq' is 0.50 what is the Delta G (degree prime) in kJ/mol?

B) The conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by an isomerase enzyme. Under cellular conditions (37*C), the glucose-6-phosphate is 6.6 uM and the fructose-6-phosphate is 1.3 uM. If the keq' is 0.50 what is the Delta G in kJ/mol? (Use the Delta G (degree prime) from the previous question)

Explanation / Answer

(A)

dG = -RT ln (Keq)

Putting values:

dG0 = -8.314*273*ln(0.5) = 1.573 kJ/mol

(B)

dG = dG0 + RT*ln(Q)

Putting values:

dG = 1573 + 8.314*310*ln(1.3/6.6)

Solving we get:

dG = -2.614 kJ/mol

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