#58,59,60,62 circled For the following compound, draw its conjugate acid. draw i

Question

#58,59,60,62 circled For the following compound, draw its conjugate acid. draw its conjugate base. HOCH_2 CH_2CH_2NH_2 Rank the following compounds from strongest to weakest acid CH_3CH_2OH CH_3 CH_2 NH_2 CH_3 CH_2 SH CH_3CH_2CH_3 For each of the following compounds, draw the form predominates at pH = 3. pH = 6, pH = 10, and pH = 14: Give the products of the following acid-base reactions and indicate whether reactants or products are favored at equilibrium. (Use the pK_ a values that a given in Section 2.3.) CH_3 CH_2 OH + NH_2 rlhar CH_3 CH_2 OH + HCl rlhar Rank the following alcohols from strongest to weakest acid. Explain the relative acidities. CH_2=CHCH_2OH CH_3CH_2CH_2OH HC=CCH_2 OH

Explanation / Answer

58) Here, the given compound has both acid and basic part. OH group represents the acidic part and NH2 group represent the basic part, that is because as OH group that donates the hydrogen ion and NH2 group that accepts the proton.

So here, OH-CH2-CH2-CH2-NH2 this compound has conjugated base as, -O-CH2-CH2-CH2-NH2

and conjugated acid as, OH-CH2-CH2-CH2-NH3+

59) Here propane has highest acidic strength because compare to other given copmounds it doesn not has the electron withdrawing group, so it can easily donates the proton (H+) .As we have already know, the compound which donates proton it is an acid.

Between ethanol and thiol (sulphur contained compound) thiol has more acidic than ethanol because, in ehanol it has oxygen atom which is more electronegative than sulphur present in thiol, So as electronagativity increses it is difficult to donate the proton hence its acidity decreases.

And compare to oxygen and sulphur, nitrogen is more electronagative, So the given ehanamine does not shows the acidic property,

So we can write the increasing order of their acidity as,

CH3CH2NH2<CH3CH2OH<CH3CH2SH<CH3CH2CH3

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