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//my x kb d L http 40-814 24/Homework%205%281%29.pdf https:// /bbcswebdav dt-Content-rid 1/courses EE App My ASU IBK Blackboard P MyMathLab P Mastering Physics I P P Sign In IMasteringc... WA webAssign C chegg Study IGuid... DSPGaming D Universatile Music Bio 340 Homework 5Due Fri., Sep25, 3:30 pm General Genetics Fall, 2015 1) 7mutations were found in tribbles that had the same phenotype. They were crossed in pairwise combinations and produced the following results a b c d e f g e- d+ c+ a. How many cistrons are present? b. Which mutations are in each cistron? 2) The Drosophila genes black (body) and dumpy (wing) are located on the second chromosome. A cross is made between wild type heterozygous females and homozygous black dumpy males that gave the following progeny: wt: 360 b103 d 97 b, d 314 a. Diagram this cross b. Are these genes linked and if so, what is the distance between them. 3) On the web at http://www.genome st html (The Kegg catalog o for future problems you will find the master list for geneome sequences. Under plants, Saccharomycescerevisiae(a yeast), click on "sce n the left column. Under "Original DB' click on SGD to go to the Stanford site. Then click on 'site map' on the top right, scroll down to "Historic Data' and click on Physical & Genetic Maps'. You will find a key to the 16 yeast chromosomes. Click on XIV (chromosome 14) a. Draw chromosome 14 to scale in kbp (kilo base pairs) showing the position of the centromere and the three genes MSB3, NRD1 and SRP1 Show your scale distance on the chromosome b. How far apart in kb are MSB3 and SRP1? ca How far are each from the centromere? Other bookmarksExplanation / Answer
2) Cross will be
Recombinants = 97 + 103 = 200
Total offsprings = 360 + 97 + 103 + 314 = 874
Recombination = 200 / 874 = 22.88%
Distance between genes = 22.88 cM.
And yes the genes are linked as they are on same chromosome.
Female Male Bb Dd X bb dd BD Bd bD bd bd Bb Dd Bb dd bb Dd bb dd 360 97 103 314 RecombinantsRelated Questions
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