Determine how many electrons could be held by the n = 4 shell. (you will have to

Question

Determine how many electrons could be held by the n = 4 shell. (you will have to consider which subshells are present, the number of orbitals in each subshell, and the number of electrons held by each orbital.) Information needed Attempt this question without getting help or using any resources/notes -use only a periodic table Write the complete electron configuration, abbreviated electron configuration, and valence electron configuration for Se. Complete electron configuration Abbreviated electron configuration Valence electron configuration

Explanation / Answer

Answer:

Question-1:

Number of electrons in the shell = 2n2

n = shell number

n=4 given in the querstion

So the number of electrons = 2 x 42

   = 2 x 16

   = 32

Number of Orbitals = n2

n = shell number

here n = 4

Number of Orbitals = 42

= 16

shells are equal to the principle quantum number

n = 1, 2 , 3...... etc.

Subshells are the Orbitals like s,p,d and f

These subshells containes Orbitals

s containes 1 orbital that is s-orbital

p containes px , py and pz

d containes 5 orbitals and f containes 7 Orbitals.

Question-2:

Se full electron configuration:1s22s22p63s23p63d10 4s2 4p4

Se abbreviated electron configuration: [Ar] 3d10 4s2 4p4

Valency electron configuration: 4s2 4p4

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