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would the calculated value of the molarity of the NaOH solution be too high or t

ID: 535248 • Letter: W

Question

would the calculated value of the molarity of the NaOH solution be too high or too low or unchanged if the following errors were made? Explain answers please.
A. the buret tip was too far above the mouth of the flask and two drops of the NaOH ran down the outside of the flask
B. An air bubble was in the tip of the buret when the student started the titration
Please explain answers would the calculated value of the molarity of the NaOH solution be too high or too low or unchanged if the following errors were made? Explain answers please.
A. the buret tip was too far above the mouth of the flask and two drops of the NaOH ran down the outside of the flask
B. An air bubble was in the tip of the buret when the student started the titration
Please explain answers would the calculated value of the molarity of the NaOH solution be too high or too low or unchanged if the following errors were made? Explain answers please.
A. the buret tip was too far above the mouth of the flask and two drops of the NaOH ran down the outside of the flask
B. An air bubble was in the tip of the buret when the student started the titration
Please explain answers

Explanation / Answer

Answer:

A) If the NaOH is ran ouit side the flask, That means the concentration of the NaOH decreases than actual value. Hence the caluculated Molarity value is lower than the actual value.

B) The presence of the air bubble means the volume is less than the actual.

According to the Molarity principle

M = Number of moles / Volume in Liter

The presence of bubble the volume decreases, By applying the volume in the principle the Molarity increases.

Hence the caluculated Molarity value is more than the actual value.