Experiment 13 involves determining the identity of an aqueous solution by examin

Question

Experiment 13 involves determining the identity of an aqueous solution by examining whether it forms a precipitate when combined with another known or unknown aqueous solution 1. Complete the following table using the solubility rules provided here. (NH4)SO4 158-2664 (R) is 158-1210 No Precipitate No Precipitate Precipitate No Precipitate No Precipitate You are You are You are You are You are u(NO. Previous Previous Previous Previous correct. correct. correct correct. 2 Your receipt no Tries Your receipt no Your receipt no Tries Your receipt no Tries receipt no. s 158-3940 s 158-4770 is 158-6921 s 158-4821 s 158-4877 No Precipitate Precipitate Precipitate Pre pitate You are You are You are You are Bac correct. Previous correct Previous correct. Previous correct. Your receipt no Your receipt no. Your receipt no Tries You receipt no. s 158-266 158-9058 s 158-3633 s 158-9768 No Precipitate No Precipitate No Precipitate You are You are You are Previous correct. Previous Correct. Your receipt no Your receipt no You receipt no. is 158-1186 s 158-4910 s 158-2505 Na CO is 158-7077 No Precipitate You are NH4)2SO4 correct. receipt no. s 158-3631 (2 ZnSO Zn(NO3)2 Zn(NO3)2 No Precipitate You are correct Previous Your receipt no. is Tries Tries 58-5970 E No Precipitate You are correct Previous Your receipt no. is Tries Tries 158-5181 Precipitate Previous You are correct Previous Your receipt no. is Tries Tries 158-7559 Incorrect. Tries 111 Previous No Precipitate You are correct Previous Your receipt no. is Tries Tries 158-6385 No Precipitate You are correct. our receipt no. Previous is Tries 158-3821

Explanation / Answer

Solubility of compounds

The chart given above,

Zn(NO3)2 + Na2CO3 --> ZnCO3 + 2NaNO3

ZnCO3 is insoluble and forms precipitate.

1 = ZnCO3

2 = BaCO3

3 = CuCO3

5 = NaCl

6 = NH4Cl

7 = Na2SO4

Colorless spots are no precipitate. Dark spots are for precipitate

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