According to the following equation, propane (C_3H_8 - a gas) combines with oxyg

Question

According to the following equation, propane (C_3H_8 - a gas) combines with oxygen to form carbon dioxide and water vapor: C_3H_8 + 5 O_2 rightarrow 3 CO_2 + 4 H_2O Mow many liters of water vapor are produced from 4 liters of propane? (Assume that the volumes of propane gas and oxygen gas: carbon dioxide gas, water vapor are measured at the same temperature and pressure.) 16 liters 8 liters 4 liters 12 liters 20 liters According to the following equation (representing a reaction which involves only gaseous substances), ethene (C_2H_4) combines with oxygen to form carbon dioxide and water vapor: C_2H_4 + 3 O_2 rightarrow 2 CO_2 + 2 H_2O How many liters of carbon dioxide are produced form 6 liters of ethane? (Assume that the volumes of ethene gas, oxygen gas, carbon dioxide gas, and water vapor arc measured at the same temperature and pressure.) 2L 3 L 6 L 12 L 8 The molecular weight of a gas is 16.0 amu. What volume would 12.0 g of this gas occupy at STP? 11.2 L 16.8 L 29.9 L 22.4 L 33.6 L What is the volume of 44.0 g of CO_2 gas at STP? (f. mass CO_12 - 44.01 amu) 40 L 22.4 L 2.00 L 896 L 44.8 L A sample of a gas occupies a volume of 8.60L at 67 degree C and 748 mmHg. How many moles of the gas are present? 0.303 mol 0.455 mol 0.175 mol 3.11 mol 0.393 mol Carbon monoxide (CO) is a very toxic, colorless, and odorless gas. What is the pressure in atmospheres exerted by 69.8 g of the gas in a steel cylinder with a volume of 8.00 L at 10 degree C? (f. mass CO = 28.01 amu) 8.00 atm 7.24 atm 3.21 atm 4.90 atm 3.97 atm Calculate the volume occupied by 3.61 moles of CO_2 at 4.29 atmospheres pressure and 27 degree C. 13.57 L 9.34 L 12.8 L 10.4 L 20.7 L

Explanation / Answer

11)

from given equation,

1 volume of propane produces 4 volume of H2O

so,

4 litre of propane produces 4*4 = 16 L of H2O

Answer: a

12)

from given equation,

1 volume of ethene produces 2 volume of CO2

so,

6 litre of ethene produces 6*2 = 12 L of CO2

Answer: c

13)

number of mol = mass / molar mass

= 12.0 g / 16 g/mol

= 0.75 mol

volume at STP = number of mol * 22.4 L

= 0.75 mol * 22.4 L

= 16.8 L

Answer: b

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