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Urea, NH_2CONH_2, (FM = 60.06 g/mol) is a nitrogen fertilizer that is manufactur

ID: 535846 • Letter: U

Question

Urea, NH_2CONH_2, (FM = 60.06 g/mol) is a nitrogen fertilizer that is manufactured from ammonia and carbon dioxide. 2 NH _3 (g) + CO_2 (g) rightarrow NH_2CONH_2(aq) + H_2O_(l) What volume of ammonia (NH_3) at 25 degree C and 1.50 atm is needed to produce 908 g (2 lbs) of urea? The heat of vaporization of water is 44 kJ/mol. How much energy is released when 1 gram of steam condenses into liquid water? The heat from 168 g of steam is used to heat a room containing 6.44 times 10^4 g of air (20 ft times 12 ft times 8 ft). The specific heat of air is 1.015 J/(g* degree C). What is the change in air temperature assuming all the heat from the steam is absorbed by the air? Mothballs are composed primarily of the hydrocarbon naphthalene (C_10H_10, FM = 128.17 g/mol) When 1.025 g of naphthalene is burned in a bomb calorimeter, the temperature rises from 25.8 degree C to 29.4 degree C. Find delta E_rxn for the combustion of naphthalene. The heat capacity of the calorimeter, determined in a separate experiment, is 5.11 kJ/degree C

Explanation / Answer

8)

molar mass of urea = 60.06 g/mol

mass of urea = 908 g

so,

number of mol of urea formed = mass / molar mass

= 908 g / 60.06 g/mol

= 15.12 mol

from given reaction,

mol of NH3 required = 2*moles of urea formed

= 2*15.12 mol

= 30.24 mol

Given:

P = 1.5 atm

n = 30.24 mol

T = 25.0 oC = (25.0+273) K

= 298 K

use:

P * V = n*R*T

1.50 atm * V = 30.24 mol* 0.0821 atm.L/mol.K * 25 C

V = 493 L

Answer: 493 L

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