1.) Answer the following three questions with this information. The ABO blood gr
ID: 53617 • Letter: 1
Question
1.) Answer the following three questions with this information. The ABO blood group assorts independently of the Rhesus (Rh) blood group and the MN blood group. Three alleles, IA , IB , and i, occur at the ABO locus. Two alleles, R, a dominant allele producing Rh+, and r, a recessive allele for Rh, are found at the Rh locus, and codominant alleles M and N occur at the MN locus. Each gene is autosomal.
A child with blood types O, Rh+, and MN is born to a woman who has blood types A, Rh+, and M and a man who has blood types B, Rh-, and MN. Determine the genotypes of each parent.
A) What is the mother's blood type? Select one choice for each blood group.
B) What is the father's blood type? Select one choice for each blood group.
C) What is the child's blood type? Select one choice for each blood group.
2.) What proportion of children born to a man with genotype AB Rr MN and a woman who is Ai Rr NN will have blood types B, Rh, and NN? Write all answers in the most reduced form of a fraction.
Explanation / Answer
Mom is type A, so she must lack both B allele. For her to be Rh+ she must have both dominant type or one dominat and one recessive. M is codominant. So mom's genotype would be:
A , R/R or R/r , MM or MN
Dad is type B, he must have B allele . To be Rh+ he must have at least one R. Again, he is type MN. Genotype is
A/B, R/R or R/r, and MN
Child's blood type is O , R/R . r/r , MN
For a child to be type B from parents (AB) and (A) he/she MUST inherit the genotype (B). Using a Punnett square you can see that there is a 25% chance the child will be type B and same goes forRh genotype. N is co-dominant so there is a 75% chance the child will be NN.
Probabilities multiply so: 0.25 x 0.25 x 0.75 = 0.047 = 4.7%
So there is a 4.7% chance the child will be B, r/r, NN
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