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View History Bookmarks Window Help saplinglearning com Blackboard Learn Print Calculator Periodic Table The following is a multi step reaction. The rate limitng step is unimolecular, with Aas the sole reactant. A B C D IA and IB are both 0.140 M, then the rate of reaction is 0.0010 Ms. (a) What is the rate of the reaction flANis doubled? 0.002 M/s (b Starting with the originaloonoentrations what is the rate ofthe reaction flBlis doubled? 0.28 M/S 100 (o originalconcentrations, what is the rate of the reaction if Aland Blare both increased by a factor 0,025 M/S O Previous View Solution check Answer

Explanation / Answer

Given that rate of above reaction solely depends on the [A]. Even though it seems to be second order by seeing the balanced chemical equation

Given that, rate limiting depend only depend on unimolecular concentration of A

rate = k[A]

Thus

concentration of A is doubled.

let the initial concentration be x and rate r if concentration of a doubled means 2x

r = k x

if new rate = k 2x= 2kx = 2 r

that is rate is doubled. given that x = 0.001 M/s

the new rate is 0.002 M/s

b).

Since,

rate limiting depend on only on the unimolecular concentration of A

rate = k[A]

on varying concentration B will not affect the reaction rate.

the answer is 0.001 M/s

c) if concentrations of A and B are increased by 5 times. As discussed earlier, the concentration of B doesn't have any influence on the rate.

Thus concentration of A only have influence and it is increased by 5 times

the rate will increase by 5 times

thus new rate is 0.005 M/s

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