Orders of the Reaction. Rate Constant Determination Reaction 6I^-(aq) + BrO^-_3(

Question

Orders of the Reaction. Rate Constant Determination Reaction 6I^-(aq) + BrO^-_3(aq) + 6H^+(aq) rightarrow 3I_2(aq) + Br^-(aq) + 3H_2O rate = k(I^-) (BrO_3) (H^+) = Delta (BrO6-_3)/t In all the reaction mixtures used in the experiment, the color change occurred when a constant predetermined number of moles of BrO^-_3, had been used up by the reaction. The color "clock" allows you to measure the time required for this fixed number of moles of Bros to react. The rate of each reaction is determined by the time t required for the color to change: since in Equation 2 the change in concentration of Br^-_3, ion, Delta(BrO^-_3), is the same in each mixture, the relative rate of each reaction inversely proportional to the time t. Since we are than mainly concerned with relative rather absolute rate, we will for convenience take all reaction rate as being equal to 1000/t. Fill in the following table, first calculating the relative for each mixture.

Explanation / Answer

Relative rate of a reaction is defined as the rate of the reaction at a particular point of time. According to the given equation (2) we can see, rate = (BrO3-) /t. This means, relative rate of the reaction is inversely proportional to the time t. Here, you have to take relative rate of reaction = 1000 / t ( for convenience). You have to note down the time (t) required for the color to change for each reaction mixture and then divide 1000 by the value of t for each reaction mixture to get the relative rate of reaction for each reaction mixture. This is relative rate, not the actual value of the rate of the reaction.

Example:

Suppose t = 20 s then relative rate of reaction = (1000 / t) = (1000 / 20) = 50

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