Using only a periodic table, write the full electron configuration for each of t

Question

Using only a periodic table, write the full electron configuration for each of the following elements. Then identify the valence electrons. Put superscripts in parentheses (For example: He = 1s(2), Li = 1s (2) 2s(1)) (a) Mg Full electron configuration: Valence electrons: (b) P Full electron configuration: Valence electrons: (c) K Full electron configuration: Valence electrons: (d) F Full electron configuration: Valence electrons: (e) Se Full electron configuration: Valence electrons: (f) N Full electron configuration: Valence electrons:

Explanation / Answer

a)

Number of electron in Mg = 12

Electronic configuration is 1s(2)2s(2)2p(6)3s(2)

valence orbital is n=3 in which there are 2 electrons

valence electrons: 2

b)

Number of electron in P = 15

Electronic configuration is 1s(2)2s(2)2p(6)3s(2)3p(3)

valence orbital is n=3 in which there are 5 electrons

valence electrons: 5

c)

Number of electron in K = 19

Electronic configuration is 1s(2)2s(2)2p(6)3s(2)3p(6)4s(1)

valence orbital is n=4 in which there are 1 electrons

valence electrons: 1

d)

Number of electron in F = 9

Electronic configuration is 1s(2)2s(2)2p(5)

valence orbital is n=2 in which there are 7 electrons

valence electrons: 7

e)

Number of electron in Se = 34

Electronic configuration is 1s(2)2s(2)2p(6)3s(2)3p(6)4s(2)4p(4)

valence orbital is n=4 in which there are 6 electrons

valence electrons: 6

f)

Number of electron in N = 7

Electronic configuration is 1s(2)2s(2)2p(3)

valence orbital is n=2 in which there are 5 electrons

valence electrons: 5

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